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Dehumidification Energy Calculator

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Input Parameters

Unit System

Inlet Conditions

Outlet Conditions

Process Information

This calculator determines the energy required to remove moisture from air through cooling and condensation. Energy includes both latent and sensible cooling.

Energy Analysis

Energy Requirements

30,249
Total Energy BTU/hr
24,849
Latent BTU/hr
5,400
Sensible BTU/hr

Moisture Removal

Moisture Removal Rate23.67 lb/hr
Condensate Flow2.84 gal/hr
Humidity Reduction25 % RH

Humidity Ratios

Inlet Humidity Ratio0.0114 lb/lb
Outlet Humidity Ratio0.00618 lb/lb
Change in Humidity Ratio0.00526 lb/lb

Performance Metrics

Specific Energy1278 BTU/lb water
Power Requirement8.9 kW
Energy per CFM30.2 BTU/hr/CFM

System Sizing

Required Capacity: 2.5 tons
(30,249 BTU/hr)

Energy Breakdown

Energy Distribution

Detailed Dehumidification Analysis

Process Analysis

Latent Load Ratio:82%
Sensible Load Ratio:18%
Moisture Density:0.0237 lb/CFM
Condensate Rate:170.3 gal/day

Equipment Sizing

Cooling Coil Capacity:2.5 tons
Compressor Power:2.5 kW
Condensate Drain:10 GPH
Reheat Load (est):0.8 tons

Operating Analysis

Power Consumption:8.9 kW
Daily Energy Cost:$25.53
Annual Energy Cost:$9319
Water Removal Cost:$0.04/lb

Dehumidification Methods Comparison

MethodEnergy (BTU/lb)Relative CostApplication
Cooling Coil (Current)12781.0xGeneral HVAC
Desiccant Wheel800-12000.8xLow humidity required
Heat Pump Dehumidifier600-9000.6xDedicated dehumidification
Refrigerant Dehumidifier700-10000.7xPool/spa applications

Dehumidification Energy Calculation Steps

1

Calculate Inlet and Outlet Humidity Ratios

Formula:
W=0.621945×PvPatm−PvW = 0.621945 \times \frac{P_v}{P_{atm} - P_v}
Calculation:
Winlet=f(80°F,70%)Woutlet=f(75°F,45%)W_{inlet} = f(80°F, 70\%)\\W_{outlet} = f(75°F, 45\%)
Result:
Winlet=0.0114,Woutlet=0.0062 lb water/lb dry airW_{inlet} = 0.0114, W_{outlet} = 0.0062 \text{ lb water/lb dry air}
2

Calculate Mass Flow Rate of Dry Air

Formula:
m˙air=Q×ρair\dot{m}_{air} = Q \times \rho_{air}
Calculation:
m˙air=1000×0.075\dot{m}_{air} = 1000 \times 0.075
Result:
75.0 lb/min75.0 \text{ lb/min}
3

Calculate Moisture Removal Rate

Formula:
m˙moisture=m˙air×(Winlet−Woutlet)×60\dot{m}_{moisture} = \dot{m}_{air} \times (W_{inlet} - W_{outlet}) \times 60
Calculation:
m˙moisture=75.0×(0.0114−0.0062)×60\dot{m}_{moisture} = 75.0 \times (0.0114 - 0.0062) \times 60
Result:
23.67 lb/hr23.67 \text{ lb/hr}
4

Calculate Latent Cooling Load

Formula:
Qlatent=m˙moisture×hfgQ_{latent} = \dot{m}_{moisture} \times h_{fg}
Calculation:
Qlatent=23.67×1050Q_{latent} = 23.67 \times 1050
Result:
24849 BTU/hr24849 \text{ BTU/hr}
5

Calculate Sensible Cooling Load

Formula:
Qsensible=m˙air×cp×ΔT×60Q_{sensible} = \dot{m}_{air} \times c_p \times \Delta T \times 60
Calculation:
Qsensible=75.0×0.24×5.0×60Q_{sensible} = 75.0 \times 0.24 \times 5.0 \times 60
Result:
5400 BTU/hr5400 \text{ BTU/hr}
6

Calculate Total Energy Required

Formula:
Qtotal=Qlatent+QsensibleQ_{total} = Q_{latent} + Q_{sensible}
Calculation:
Qtotal=24849+5400Q_{total} = 24849 + 5400
Result:
30249 BTU/hr30249 \text{ BTU/hr}
7

Calculate Specific Energy

Formula:
Especific=Qtotalm˙moistureE_{specific} = \frac{Q_{total}}{\dot{m}_{moisture}}
Calculation:
Especific=3024923.67E_{specific} = \frac{30249}{23.67}
Result:
1278 BTU/lb water1278 \text{ BTU/lb water}